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opt: calculate the interval for ReleaseTimeout() based on a default count (#327) 

This PR reverts #325 to some extent.
This commit is contained in:
Andy Pan 2024-06-17 20:13:15 +08:00 committed by GitHub
parent b2374d5ae4
commit 3ffd3daa37
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3 changed files with 6 additions and 4 deletions
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2
ants.go
View File

@ -98,7 +98,7 @@ var (
const (
nowTimeUpdateInterval = 500 * time.Millisecond
releaseTimeoutInterval = 100 * time.Millisecond
releaseTimeoutCount = 10
)
// Logger is used for logging formatted messages.

3
pool.go
View File

@ -299,6 +299,7 @@ func (p *Pool) ReleaseTimeout(timeout time.Duration) error {
}
p.Release()
interval := timeout / releaseTimeoutCount
endTime := time.Now().Add(timeout)
for time.Now().Before(endTime) {
if p.Running() == 0 &&
@ -306,7 +307,7 @@ func (p *Pool) ReleaseTimeout(timeout time.Duration) error {
atomic.LoadInt32(&p.ticktockDone) == 1 {
return nil
}
time.Sleep(releaseTimeoutInterval)
time.Sleep(interval)
}
return ErrTimeout
}

3
pool_func.go
View File

@ -304,6 +304,7 @@ func (p *PoolWithFunc) ReleaseTimeout(timeout time.Duration) error {
}
p.Release()
interval := timeout / releaseTimeoutCount
endTime := time.Now().Add(timeout)
for time.Now().Before(endTime) {
if p.Running() == 0 &&
@ -311,7 +312,7 @@ func (p *PoolWithFunc) ReleaseTimeout(timeout time.Duration) error {
atomic.LoadInt32(&p.ticktockDone) == 1 {
return nil
}
time.Sleep(releaseTimeoutInterval)
time.Sleep(interval)
}
return ErrTimeout
}